A body of mass 0.4 text{ kg} performs simple | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given: Mass $m = 0.4 	ext{ kg}$, Restoring force $F = 0.4 	ext{ N}$, Displacement $x = 4 	ext{ cm} = 0.04 	ext{ m}$.$1$. The restoring force i

Vedclass · Accepted Answer

$10 	ext{ N/m}, 1 	ext{ m/s}^2$

Vedclass · Answer

(A) Given: Mass $m = 0.4 	ext{ kg}$, Restoring force $F = 0.4 	ext{ N}$, Displacement $x = 4 	ext{ cm} = 0.04 	ext{ m}$.$1$. The restoring force in simple harmonic motion is given by $F = kx$, where $k$ is the force constant.$k = F / x = 0.4 	ext{ N} / 0.04 	ext{ m} = 10 	ext{ N/m}$.$2$. The acceleration $a$ is given by $F = ma$, so $a = F / m$.$a = 0.4 	ext{ N} / 0.4 	ext{ kg} = 1 	ext{ m/s}^2$.Thus, the force constant is $10 	ext{ N/m}$ and the magnitude of acceleration is $1 	ext{ m/s}^2$.

$A$ body of mass $0.4 \text{ kg}$ performs simple harmonic motion. It experiences a restoring force of $0.4 \text{ N}$ when its displacement from the mean position is $4 \text{ cm}$. The force constant and magnitude of acceleration respectively are

Similar Questions

The $x-t$ graph of a particle undergoing simple harmonic motion is shown below. The acceleration of the particle at $t = 4/3 \,s$ is

This is the position-time graph of a mass on a spring. What can you say about the velocity and force at the instant indicated by the dashed line? (Positive direction is to the right.)

What is the maximum acceleration of a particle performing $SHM$ given by the equation $y = 2\sin \left( {\frac{{\pi t}}{2} + \phi } \right)$,where $y$ is in $cm$?

What is the force constant of a particle executing $SHM$?

The maximum force acting on a particle executing simple harmonic motion is $10 \,N$. The force on the particle when it is midway between mean and extreme positions will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module