A wire is under tension of 2 text{ kg wt} and | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The speed of a wave in a stretched wire is given by $v = \sqrt{\frac{T}{\mu}}$, where $T$ is the tension and $\mu$ is the linear mass density.From

Vedclass · Accepted Answer

$16$

Vedclass · Answer

(C) The speed of a wave in a stretched wire is given by $v = \sqrt{\frac{T}{\mu}}$, where $T$ is the tension and $\mu$ is the linear mass density.From this relation, we see that $v \propto \sqrt{T}$.Let the initial tension be $T_1 = 2 	ext{ kg wt}$ and the initial speed be $v_1 = v$.Let the final tension be $T_2$ and the final speed be $v_2 = 3v$.Using the proportionality $v \propto \sqrt{T}$, we have $\frac{v_2}{v_1} = \sqrt{\frac{T_2}{T_1}}$.Substituting the values: $\frac{3v}{v} = \sqrt{\frac{T_2}{2}} \implies 3 = \sqrt{\frac{T_2}{2}}$.Squaring both sides: $9 = \frac{T_2}{2} \implies T_2 = 18 	ext{ kg wt}$.The increase in tension is $\Delta T = T_2 - T_1 = 18 - 2 = 16 	ext{ kg wt}$.

$A$ wire is under tension of $2 \text{ kg wt}$ and a wave is travelling through it with some speed. Tension in the wire is so increased that the wave travels through it with thrice the original speed. The increase in tension is (in kg wt)

Similar Questions

The equation of a wave on a string of linear mass density $0.04 \ kg \ m^{-1}$ is given by $y = 0.02 \sin \left[ 2\pi \left( \frac{t}{0.04 \ s} - \frac{x}{0.50 \ m} \right) \right] \ m$. The tension in the string is .... $N$.

$A$ string of mass $2.50 \;kg$ is under a tension of $200\; N$. The length of the stretched string is $20.0 \;m$. If the transverse jerk is struck at one end of the string,how long (in $sec$) does the disturbance take to reach the other end?

$A$ string of length $L$ is stretched by $\frac{L}{20}$ and the speed of transverse waves along it is $v$. The speed of the wave when it is stretched by $\frac{L}{10}$ will be (assume that Hooke's law is applicable).

$A$ uniform metal wire has length $L$,mass $M$,and density $\rho$. It is under tension $T$,and $v$ is the speed of a transverse wave along the wire. The area of cross-section of the wire is:

$A$ string of mass $M$ is under a tension $T$. The length of the string is $L$. $A$ transverse wave starts at one end of the string. The time required for the disturbance to reach the other end is

Vedclass Test Series

Exam Paper Generator

Online Exam Module