$A$ ray of light is incident at the polarising angle $\theta$ on an air-glass interface. If $\lambda_a$ and $\lambda_g$ are the wavelengths of light in air and glass respectively, then:

The polarising angle for a transparent medium is $\theta$ and $V$ is the speed of light in that medium. The relation between $\theta$ and $V$ is (where $c$ is the velocity of light in vacuum):

$A$ ray of light is incident on the surface of a glass plate at an angle of incidence equal to Brewster's angle $\Phi$. If $\mu$ denotes the refractive index of glass with respect to air, then what will be the angle between the reflected and refracted rays?

The angle of incidence at which reflected light is completely polarized for reflection from air to a medium of refractive index $n$ is:

The polarising angle for water is $53^\circ 4'$. If light is incident at this angle on the surface of water and reflected, the angle of refraction is:

Consider a tank made of glass (refractive index $1.5$) with a thick bottom. It is filled with a liquid of refractive index $\mu$. $A$ student finds that,irrespective of what the incident angle $i$ (see figure) is for a beam of light entering the liquid,the light reflected from the liquid-glass interface is never completely polarized. For this to happen,the minimum value of $\mu$ is