$A$ solution of a non-volatile solute has a boiling point elevation of $0.70 \text{ K}$. If $K_b$ for the solvent is $2.44 \text{ K kg mol}^{-1}$, what is the molality of the solution (in $\text{ m}$)?

What is the relation between the molar mass of a solute and the boiling point elevation?

The boiling point of benzene is $353.23 \, K$. When $1.80 \, g$ of a nonvolatile solute was dissolved in $90 \, g$ of benzene,the boiling point is raised to $354.11 \, K$. The molar mass of the solute is $........ \, g \, mol^{-1}$. $[K_b \text{ for benzene} = 2.53 \, K \, kg \, mol^{-1}]$

Two different solutions were prepared by dissolving sucrose in water having concentrations of $1 \ m$ and $2 \ m$ respectively. The value of $(T_2 - T_1)$ will be ........... $K$. (Given: $K_b$ for water $= 0.52 \ K \ kg \ mol^{-1}$)

The elevation in boiling point for a $0.1 \ m$ solution of a solute in $500 \ g$ of benzene is $0.51 \ K$. If $1000 \ g$ of a $0.1 \ m$ solution of the same solute in benzene is added to the above solution,the $\Delta T_b$ for the resulting solution will be ............... $K$.

When common salt is dissolved in water,