A compound forms an hcp structure. What is th | vedclass

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(B) $1$. In an $hcp$ structure, if the number of atoms is $N$, then the number of tetrahedral voids is $2N$.$2$. The number of atoms in $0.8 	ext{ mo

Vedclass · Accepted Answer

$9.635 	imes 10^{23}$

Vedclass · Answer

(B) $1$. In an $hcp$ structure, if the number of atoms is $N$, then the number of tetrahedral voids is $2N$.$2$. The number of atoms in $0.8 	ext{ mol}$ is $0.8 	imes N_A$, where $N_A = 6.022 	imes 10^{23} 	ext{ mol}^{-1}$.$3$. Number of tetrahedral voids $= 2 	imes (0.8 	imes N_A) = 1.6 	imes N_A$.$4$. Calculation: $1.6 	imes 6.022 	imes 10^{23} = 9.6352 	imes 10^{23}$.$5$. Thus, the correct option is $B$.

$A$ compound forms an $hcp$ structure. What is the total number of tetrahedral voids formed in $0.8 \text{ mol}$ of this compound?

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