int frac{dx}{sin^2 x cos^2 x} = | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) To solve the integral $\int \frac{dx}{\sin^2 x \cos^2 x}$,we use the trigonometric identity $1 = \sin^2 x + \cos^2 x$.Substituting this into the n

Vedclass · Accepted Answer

$	an x - \cot x + c$

Vedclass · Answer

(C) To solve the integral $\int \frac{dx}{\sin^2 x \cos^2 x}$,we use the trigonometric identity $1 = \sin^2 x + \cos^2 x$.Substituting this into the numerator,we get:$\int \frac{\sin^2 x + \cos^2 x}{\sin^2 x \cos^2 x} dx$Splitting the fraction,we have:$\int \left( \frac{\sin^2 x}{\sin^2 x \cos^2 x} + \frac{\cos^2 x}{\sin^2 x \cos^2 x} ight) dx$This simplifies to:$\int (\sec^2 x + \csc^2 x) dx$Integrating term by term,we get:$\int \sec^2 x dx + \int \csc^2 x dx = 	an x - \cot x + c$.

$\int \frac{dx}{\sin^2 x \cos^2 x} = $

Similar Questions

Write an anti-derivative for the following function using the method of inspection: $\frac{1}{x}, x \neq 0$

$\int \frac{\sin 7x}{\sin 2x \sin 5x} dx =$

The points of intersection of ${F_1}(x) = \int_2^x {(2t - 5)\,dt} $ and ${F_2}(x) = \int_0^x {2t\,dt} $ are

$\int \frac{x^4+x^2+1}{x^2-x+1} dx =$

$\int \sqrt{1+\cos x} \, dx$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module