1 text{ cm}^3 of water at its boiling point a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to the first law of thermodynamics, $\Delta Q = \Delta U + \Delta W$. Here, $\Delta Q$ is the total heat absorbed, $\Delta U$ is the cha

Vedclass · Accepted Answer

$500$

Vedclass · Answer

(C) According to the first law of thermodynamics, $\Delta Q = \Delta U + \Delta W$. Here, $\Delta Q$ is the total heat absorbed, $\Delta U$ is the change in internal energy (energy spent in overcoming intermolecular forces), and $\Delta W$ is the work done against atmospheric pressure. Given: $\Delta Q = 540 	ext{ cal}$, $P = 1.013 	imes 10^5 	ext{ N/m}^2$, $V_1 = 1 	ext{ cm}^3 = 10^{-6} 	ext{ m}^3$, $V_2 = 1671 	ext{ cm}^3 = 1671 	imes 10^{-6} 	ext{ m}^3$, and $J = 4.19 	ext{ J/cal}$. Work done $\Delta W = P(V_2 - V_1) = 1.013 	imes 10^5 	imes (1671 - 1) 	imes 10^{-6} 	ext{ J} = 1.013 	imes 10^5 	imes 1670 	imes 10^{-6} 	ext{ J} \approx 169.17 	ext{ J}$. Converting work to calories: $\Delta W_{	ext{cal}} = \frac{169.17}{4.19} \approx 40.37 	ext{ cal}$. Internal energy change $\Delta U = \Delta Q - \Delta W_{	ext{cal}} = 540 - 40.37 \approx 500 	ext{ cal}$.

Similar Questions

In a thermodynamic process,the pressure of a fixed mass of a gas is changed in such a manner that the gas releases $30 \ J$ of heat and $10 \ J$ of work is done on the gas. If the initial internal energy of the gas was $30 \ J$,then the final internal energy will be ........ $J$.

$540$ calories of heat convert $1$ cubic centimeter of water at $100^{\circ}C$ into $1671$ cubic centimeter of steam at $100^{\circ}C$ at a pressure of one atmosphere. Then the work done against the atmospheric pressure is nearly ...... $cal$.

$A$ gas absorbs $18 \ J$ of heat and work done on the gas is $12 \ J$. Then the change in internal energy of the gas is: (in $J$)

$A$ source supplies heat to a system at the rate of $1000 \, W$. If the system performs work at a rate of $200 \, W$,the rate at which the internal energy of the system increases is $....... \, W$.

When $110 \ J$ of heat is supplied to a system and the change in internal energy is $40 \ J$,the work done is .......... $J$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module