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Question

(D) The unit of pressure is $Pascal$ $(Pa)$,which has the dimensional formula $[M L^{-1} T^{-2}]$.Therefore,the dimensional formula of $Pascal-second$

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Coefficient of viscosity

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(D) The unit of pressure is $Pascal$ $(Pa)$,which has the dimensional formula $[M L^{-1} T^{-2}]$.Therefore,the dimensional formula of $Pascal-second$ $(Pa \cdot s)$ is $[M L^{-1} T^{-2}] 	imes [T] = [M L^{-1} T^{-1}]$.The coefficient of viscosity $(\eta)$ is defined by the formula:$\eta = \frac{F}{A (\Delta v / \Delta z)}$where $F$ is force,$A$ is area,and $\frac{\Delta v}{\Delta z}$ is the velocity gradient.The dimensions of $\eta$ are:$	ext{Dimensions of } \eta = \frac{[M L T^{-2}]}{[L^2] [T^{-1}]} = [M L^{-1} T^{-1}]$.Since the dimensions of $Pascal-second$ match the dimensions of the coefficient of viscosity,the correct option is $D$.

List-$I$	List-$II$
$A$. Spring constant	$I$. $ML^2 T^{-2} K^{-1}$
$B$. Thermal conductivity	$II$. $ML^0 T^{-2}$
$C$. Boltzmann constant	$III$. $ML^2 T^{-3} A^{-2}$
$D$. Inductive reactance	$IV$. $MLT^{-3} K^{-1}$

List-$I$	List-$II$
$A$. Boltzmann constant	$I$. $[ML^0T^0]$
$B$. Coefficient of viscosity	$II$. $[ML^{-1}T^{-1}]$
$C$. Water equivalent	$III$. $[ML^2T^{-2}K^{-1}]$
$D$. Coefficient of thermal conductivity	$IV$. $[MLT^{-3}K^{-1}]$

$Pascal-Second$ has the dimension of:

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