In the Krebs cycle,the acceptor of acetyl CoA | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The Krebs cycle (also known as the Citric Acid Cycle) begins with the condensation of an acetyl group from acetyl $CoA$ $(2C)$ with a four-carbon

Vedclass · Accepted Answer

Oxaloacetic acid

Vedclass · Answer

(D) The Krebs cycle (also known as the Citric Acid Cycle) begins with the condensation of an acetyl group from acetyl $CoA$ $(2C)$ with a four-carbon compound called oxaloacetic acid ($OAA$,$4C$).This reaction is catalyzed by the enzyme citrate synthase and results in the formation of citric acid $(6C)$.Therefore,oxaloacetic acid acts as the initial acceptor of the acetyl group in the Krebs cycle.

In the Krebs cycle,the acceptor of acetyl $CoA$ is .........

Similar Questions

The citric acid cycle begins with the reaction . . . . . . .

Which enzyme is required for the following conversion?
Pyruvic acid + $CoA + NAD^+ \longrightarrow$ Acetyl $CoA + CO_2 + NADH + H^+$

How many substrate-level $ATP$ (or $GTP$) molecules are synthesized when $\alpha$-ketoglutaric acid is converted into succinic acid in the Krebs cycle?

Acetyl $Co-A$ binds to oxaloacetic acid to form

In the given organelle,where does the Krebs cycle take place?

Vedclass Test Series

Exam Paper Generator

Online Exam Module