In a DNA molecule,if the base ratio (A+T)/(G+ | vedclass

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(B) The given base ratio is $\frac{A+T}{G+C} = 0.3$.We are given that the total amount of $A+T$ nitrogenous bases is $30,000$.Substituting the value i

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$100$

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(B) The given base ratio is $\frac{A+T}{G+C} = 0.3$.We are given that the total amount of $A+T$ nitrogenous bases is $30,000$.Substituting the value into the equation: $\frac{30,000}{G+C} = 0.3$.Rearranging the equation to solve for $G+C$: $G+C = \frac{30,000}{0.3}$.$G+C = \frac{300,000}{3} = 100,000$.Therefore,the amount of $G+C$ nitrogenous bases is $100,000$.

In a $DNA$ molecule,if the base ratio $(A+T)/(G+C)$ is $0.3$ and the amount of $A+T$ nitrogenous bases is $30,000$,what will be the amount of $G+C$ nitrogenous bases in the $DNA$ (in $,000$)?

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