If the genetic code were a tetraplet (four-le | vedclass

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(C) The genetic code is based on $4$ nitrogenous bases $(A, U, G, C)$.If the code is a triplet,the number of possible codons is $4^3 = 64$.If the gene

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$256$

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(C) The genetic code is based on $4$ nitrogenous bases $(A, U, G, C)$.If the code is a triplet,the number of possible codons is $4^3 = 64$.If the genetic code were a tetraplet (four-letter code),the number of possible codons would be $4^4$.Calculating this: $4 	imes 4 	imes 4 	imes 4 = 256$.Therefore,there would be $256$ possible codons.

If the genetic code were a tetraplet (four-letter code),how many possible codons would exist for $20$ types of amino acids?

Similar Questions

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