If a DNA molecule contains 10,000 base pairs, | vedclass

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Question

(A) The distance between two consecutive base pairs in a $DNA$ double helix is $0.34 \ nm$ (or $3.4 \ \mathring{A}$). Given that the total number of b

Vedclass · Accepted Answer

$3400$

Vedclass · Answer

(A) The distance between two consecutive base pairs in a $DNA$ double helix is $0.34 \ nm$ (or $3.4 \ \mathring{A}$). Given that the total number of base pairs is $10,000$. The total length of the $DNA$ molecule is calculated as: $	ext{Length} = 	ext{Number of base pairs} 	imes 	ext{Distance between two base pairs}$ $	ext{Length} = 10,000 	imes 0.34 \ nm = 3400 \ nm$. Therefore,the correct option is $A$.

If a $DNA$ molecule contains $10,000$ base pairs,what is its length (in $nm$)?

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