How many N_2 base pairs are present in one fu | vedclass

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(C) In the $B-DNA$ structure,one full turn of the helix measures approximately $3.4 \ nm$ $(34 \ \mathring{A})$. Each base pair is spaced at a distanc

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Ten pairs

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(C) In the $B-DNA$ structure,one full turn of the helix measures approximately $3.4 \ nm$ $(34 \ \mathring{A})$. Each base pair is spaced at a distance of $0.34 \ nm$ $(3.4 \ \mathring{A})$. Therefore,the number of base pairs per turn is calculated as $3.4 \ nm / 0.34 \ nm = 10$ base pairs. Thus,there are $10$ base pairs in one full turn of the $DNA$ helix.

How many $N_2$ base pairs are present in one full turn of a $DNA$ helix?

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