(A) In $B-DNA$, the structure is a double helix with a constant diameter of $2.0\ nm$ $(20\ \text{\AA})$. Each full turn of the helix consists of $10$

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(A) In $B-DNA$, the structure is a double helix with a constant diameter of $2.0\ nm$ $(20\ \text{\AA})$. Each full turn of the helix consists of $10$ base pairs. The distance between two adjacent base pairs is $0.34\ nm$ $(3.4\ \text{\AA})$. Therefore, the length of one full turn of the helix is $10 \times 0.34\ nm = 3.4\ nm$.