What is the B-F bond order in BF_3? | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In $BF_3$,the boron atom is electron-deficient and forms three $B-F$ sigma bonds. Due to the back-bonding from the filled $2p$ orbital of fluorine

Vedclass · Accepted Answer

$\frac{4}{3}$

Vedclass · Answer

(D) In $BF_3$,the boron atom is electron-deficient and forms three $B-F$ sigma bonds. Due to the back-bonding from the filled $2p$ orbital of fluorine to the empty $2p$ orbital of boron,the $B-F$ bond acquires partial double bond character. There are $3$ equivalent resonance structures for $BF_3$. In each structure,there is one double bond and two single bonds among the three $B-F$ positions. The total number of bonds is $1 + 1 + 2 = 4$. The bond order is calculated as $\frac{	ext{Total number of bonds}}{	ext{Number of resonating structures}} = \frac{4}{3} \approx 1.33$.

What is the $B-F$ bond order in $BF_3$?

Similar Questions

$A$ transformer is used to light a $140 \, W, 24 \, V$ lamp from a $240 \, V \, AC$ mains. The current in the main cable is $0.7 \, A$. The efficiency of the transformer is......$\%$

In the case of alkali metals,the covalent character decreases in the order

$A$ sequence of how many nucleotides in messenger $RNA$ makes a codon for an amino acid?

Which of the following is the sweetest sugar?

The angle between the lines whose direction cosines satisfy the equations $l+m+n=0$ and $l^2+m^2-n^2=0$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module