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(C) When an aqueous solution of aluminum chloride $(AlCl_3)$ is heated to dryness,it undergoes hydrolysis due to the high charge density of the $Al^{3

Vedclass · Accepted Answer

$Al_2O_3$

Vedclass · Answer

(C) When an aqueous solution of aluminum chloride $(AlCl_3)$ is heated to dryness,it undergoes hydrolysis due to the high charge density of the $Al^{3+}$ ion. The reaction is: $AlCl_3 + 3H_2O \rightarrow Al(OH)_3 + 3HCl$. Upon further heating,the aluminum hydroxide loses water to form aluminum oxide: $2Al(OH)_3 \rightarrow Al_2O_3 + 3H_2O$. Therefore,the final residue obtained is aluminum oxide $(Al_2O_3)$.

What is obtained when an aqueous solution of aluminum chloride is heated to dryness?

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