$Ge(II)$ compounds are strong reducing agents,whereas $Pb(IV)$ compounds are strong oxidizing agents. This is due to:

  • A
    $Pb$ is more electropositive than $Ge$.
  • B
    The ionization potential of $Pb$ is lower than that of $Ge$.
  • C
    The ionic radii of $Pb^{2+}$ and $Pb^{4+}$ are larger than those of $Ge^{2+}$ and $Ge^{4+}$.
  • D
    The more pronounced inert pair effect in $Pb$ compared to $Ge$.

Explore More

Similar Questions

Give a brief account of the production of cement and write its properties and uses.

Difficult
View Solution

$X \xrightarrow{CoCl_2} CaCl_2 + Y \uparrow$; the effective ingredient of $X$ is

$Kieselghur$ is an amorphous form of silica which is used in filtration plants. Which of the following is true about it?

In the following reaction,identify the nature of the product formed by the complete hydrolysis of the underlined atom at $R.T.$:
$\underline{Si}Cl_4 + H_2O \longrightarrow H_4SiO_4 + HCl$

Difficult
View Solution

Which of the following statements is incorrect regarding zeolites?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo