$PbF_4$ and $PbCl_4$ exist,while $PbBr_4$ and $PbI_4$ do not exist. This is due to:
- ALarge size of $Br$ and $I$
- BStrong oxidizing nature of $Pb^{4+}$
- CStrong reducing nature of $Pb^{4+}$
- DLow electronegativity of $Br^-$ and $I^-$
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Similar Questions
$H_3PO_4$ $\xrightarrow{250\ ^oC}$ $(X)$ $\xrightarrow{600\ ^oC}$ $(Y)$
$H_3PO_4$ $\xrightarrow{600\ ^oC}$ $(Y)$
$(X)$ and $(Y)$ are:
$H_3PO_4$ $\xrightarrow{600\ ^oC}$ $(Y)$
$(X)$ and $(Y)$ are:
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View SolutionSmall quantities of $NO$ and $HNO_3$ are formed as impurities when $N_2$ is prepared from $NH_4Cl_{(aq)}$ and $NaNO_{2(aq)}$. These impurities can be removed by passing the $N_2$ gas through which of the following?
$P_2O_5$ is heated with water to give:
The oxide of nitrogen formed by thermal decomposition of $NH_4NO_3$ is
Which of the following statements is true regarding nitrogen?
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