Nitrogen forms N_2,but phosphorus prefers to | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Nitrogen has a small atomic size and high electronegativity,which allows it to form stable $p\pi-p\pi$ multiple bonds,resulting in the diatomic $N

Vedclass · Accepted Answer

$P-P$ single bond is stronger than $P \equiv P$ bond.

Vedclass · Answer

(C) Nitrogen has a small atomic size and high electronegativity,which allows it to form stable $p\pi-p\pi$ multiple bonds,resulting in the diatomic $N_2$ molecule.In contrast,phosphorus has a larger atomic size,which makes the effective overlap of $p$-orbitals for $p\pi-p\pi$ bonding difficult.Therefore,phosphorus prefers to form three $P-P$ single bonds rather than one $P \equiv P$ triple bond.Since the $P-P$ single bond is much stronger than the $\pi$-component of the $P \equiv P$ bond,phosphorus exists as a tetrahedral $P_4$ molecule.

$List-I$	$List-II$
$A$. $(NH_4)_2Cr_2O_7 \xrightarrow{\Delta}$	$I$. $H_2$
$B$. $KMnO_4 + HCl \rightarrow$	$II$. $N_2$
$C$. $Al + NaOH + H_2O \rightarrow$	$III$. $O_2$
$D$. $NaNO_3 \xrightarrow{\Delta}$	$IV$. $Cl_2$

Nitrogen forms $N_2$,but phosphorus prefers to exist as $P_4$ rather than $P_2$. Which of the following is the reason for this?

Similar Questions

Which of the following, when subjected to thermal decomposition, will liberate dinitrogen?
$(i)$ Sodium nitrate
$(ii)$ Ammonium dichromate
$(iii)$ Barium azide

Which gas is evolved when ammonium dichromate is heated?

On reaction of $Lead$ $Sulphide$ with dilute nitric acid,which of the following is not formed?

Vedclass Test Series

Exam Paper Generator

Online Exam Module