Two rotating bodies have the same angular momentum,but their moments of inertia are $I_1$ and $I_2$ respectively. If $I_1 > I_2$,which body will have a higher kinetic energy?

The position vector of a particle is $\vec{r} = (\hat{i} + 2\hat{j} - \hat{k})$ and its momentum is $\vec{p} = (3\hat{i} + 4\hat{j} - 2\hat{k})$. The angular momentum of this particle is perpendicular to:

$A$ particle is moving along a straight line parallel to $x-$ axis with constant velocity. Its angular momentum about the origin

$A$ particle is rotating in a circle with uniform speed as shown. The angular momentum of the particle with respect to the origin is .........

$A$ mass tied to a string is whirled in a horizontal circular path with a constant angular velocity and its angular momentum is $L$. If the length of the string is now halved, keeping the angular velocity the same, then the angular momentum will be:

$A$ ball of mass $1 \,kg$ is projected with a velocity of $20 \sqrt{2} \,m/s$ from the origin of an $xy$ coordinate axis system at an angle of $45^{\circ}$ with the $x$-axis (horizontal). The angular momentum [in $SI$ units] of the ball about the point of projection after $2 \,s$ of projection is [take $g = 10 \,m/s^2$] ($y$-axis is taken as vertical).