There are three genes a, b, and c. The recomb | vedclass

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(A) The recombination frequency is directly proportional to the distance between genes on a chromosome. Given: Distance between $a$ and $b = 20$ units

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$b, a, c$

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(A) The recombination frequency is directly proportional to the distance between genes on a chromosome. Given: Distance between $a$ and $b = 20$ units. Distance between $b$ and $c = 28$ units. Distance between $a$ and $c = 8$ units. To find the arrangement,we look for the additive property of distances. Here,$20 + 8 = 28$,which means the distance between $b$ and $c$ is the sum of the distances between $b-a$ and $a-c$. This implies that gene $a$ lies between $b$ and $c$. Therefore,the linear order of genes on the chromosome is $b-a-c$ or $c-a-b$.

There are three genes $a, b,$ and $c$. The recombination frequency between $a$ and $b$ is $20\%$,between $b$ and $c$ is $28\%$,and between $a$ and $c$ is $8\%$. What is the possible arrangement of these genes on the chromosome?

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