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(B) According to the Hardy-Weinberg principle,the sum of the frequencies of all alleles in a population is always equal to $1$.For two alleles $A_1$ a

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$1$

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(B) According to the Hardy-Weinberg principle,the sum of the frequencies of all alleles in a population is always equal to $1$.For two alleles $A_1$ and $A_2$,the equation is: $p + q = 1$,where $p$ is the frequency of $A_1$ and $q$ is the frequency of $A_2$.Given that the frequency of $A_1$ $(p)$ is $0$,we substitute this into the equation:$0 + q = 1$Therefore,$q = 1$.Thus,the frequency of the allele $A_2$ is $1$.

There are two alleles ($A_1$ and $A_2$) in a population. If the frequency of one allele $(A_1)$ is $0$,then the frequency of the other allele $(A_2)$ is .....

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