In a population exhibiting random mating,the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to the Hardy-Weinberg principle,the genetic equilibrium is represented by the equation $(p + q)^2 = p^2 + 2pq + q^2 = 1$,where $p$ is th

Vedclass · Accepted Answer

$32$

Vedclass · Answer

(B) According to the Hardy-Weinberg principle,the genetic equilibrium is represented by the equation $(p + q)^2 = p^2 + 2pq + q^2 = 1$,where $p$ is the frequency of the dominant allele and $q$ is the frequency of the recessive allele.Given that the frequency of the recessive allele $(q)$ is $80\%$,we have $q = 0.8$.Consequently,the frequency of the dominant allele $(p)$ is $p = 1 - q = 1 - 0.8 = 0.2$.Carrier individuals are those who are heterozygous for the recessive trait,represented by the term $2pq$ in the Hardy-Weinberg equation.Substituting the values: $2pq = 2 	imes 0.2 	imes 0.8 = 0.32$.Converting this to a percentage: $0.32 	imes 100 = 32\%$.Therefore,the frequency of carrier individuals in the population is $32\%$.

In a population exhibiting random mating,the frequency of a disease-causing recessive allele is $80\%$. What will be the frequency of carrier individuals in the population (in $\%$)?

Similar Questions

According to the Hardy-Weinberg principle,a difference in the values of measured and expected allelic frequencies indicates all of the following,except:

If the measured allele frequency differs from the expected value,what does it indicate?

$A$ gene locus has two alleles $A$ and $a$. If the frequency of the dominant allele $A$ is $0.4$,then what will be the frequency of homozygous dominant,heterozygous,and homozygous recessive individuals in the population?

What is the total sum of genes and their alleles in a population collectively called?

Recessive alleles are not lost from the gene pool. This is known as:

Vedclass Test Series

Exam Paper Generator

Online Exam Module