A plant with the genotype AABbCcDD is self-po | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To find the proportion of the $AAbbccDD$ genotype in the self-pollination of $AABbCcDD$,we analyze each gene pair independently using the law of i

Vedclass · Accepted Answer

$1/16$

Vedclass · Answer

(B) To find the proportion of the $AAbbccDD$ genotype in the self-pollination of $AABbCcDD$,we analyze each gene pair independently using the law of independent assortment:$1$. For the $AA$ genotype: $AA 	imes AA$ results in $100\%$ $AA$ (probability = $1$).$2$. For the $Bb$ genotype: $Bb 	imes Bb$ results in $1/4$ $BB$,$2/4$ $Bb$,and $1/4$ $bb$. The probability of $bb$ is $1/4$.$3$. For the $Cc$ genotype: $Cc 	imes Cc$ results in $1/4$ $CC$,$2/4$ $Cc$,and $1/4$ $cc$. The probability of $cc$ is $1/4$.$4$. For the $DD$ genotype: $DD 	imes DD$ results in $100\%$ $DD$ (probability = $1$).Multiplying these independent probabilities: $1 	imes 1/4 	imes 1/4 	imes 1 = 1/16$.

$A$ plant with the genotype $AABbCcDD$ is self-pollinated. Assuming independent assortment of the four genes,what will be the proportion of the $AAbbccDD$ genotype in the progeny?

Similar Questions

Which of the following is heterozygous for two pairs of alleles?

Probability of genotype $TTrr$ in $F_{2}$-generation of a dihybrid cross is

$A$ diploid organism is heterozygous for $4$ loci. How many types of gametes can be produced?

Describe Mendel's experiment on pea plants involving two different traits.

The dihybrid cross is associated with the principle of . . . . . . .

Vedclass Test Series

Exam Paper Generator

Online Exam Module