A dihybrid plant produced by self-pollination | vedclass

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(B) In a dihybrid cross involving self-pollination of a $TtRr$ plant,the phenotypic ratio is $9:3:3:1$ and the genotypic ratio is $1:2:1:2:4:2:1:2:1$.

Vedclass · Accepted Answer

$100$

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(B) In a dihybrid cross involving self-pollination of a $TtRr$ plant,the phenotypic ratio is $9:3:3:1$ and the genotypic ratio is $1:2:1:2:4:2:1:2:1$.Total number of seeds = $400$.The genotype $TtRr$ represents the heterozygous condition for both traits.According to the Mendelian dihybrid ratio,the probability of obtaining the $TtRr$ genotype is $4/16$ or $1/4$.Therefore,the number of seeds with the $TtRr$ genotype = $(1/4) 	imes 400 = 100$.

$A$ dihybrid plant produced by self-pollination yields $400$ seeds with $9$ different genotypes. How many seeds will have the $TtRr$ genotype?

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