In a dihybrid cross where two parents differ | vedclass

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(B) In a dihybrid cross,the $F_2$ generation follows the phenotypic ratio of $9:3:3:1$.Total number of offspring in $F_2$ generation = $16$.The trait

Vedclass · Accepted Answer

$4$

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(B) In a dihybrid cross,the $F_2$ generation follows the phenotypic ratio of $9:3:3:1$.Total number of offspring in $F_2$ generation = $16$.The trait for seed color is yellow $(Y)$ dominant over green $(y)$.According to the law of independent assortment,the phenotypic ratio for seed color alone is $3$ (yellow) : $1$ (green).Out of $16$ total offspring,the number of green seeds $(yy)$ is calculated as: $(1/4) 	imes 16 = 4$.Therefore,there will be $4$ green seeds in the $F_2$ generation.

In a dihybrid cross where two parents differ in their traits,such as yellow seeds $(YY)$ with round shape $(RR)$ and green seeds $(yy)$ with wrinkled shape $(rr)$,how many seeds out of the total $16$ in the $F_2$ generation will be green $(yy)$?

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From a mating of two dihybrid individuals $(AaBb \times AaBb)$,how many of the $16$ possible zygote combinations would be expected to contain only two dominant genes?

In Mendel's dihybrid cross experiment,how many types of genotypes are obtained in the $F_2$ generation?

$A$ cross was made by Mendel with pea plants between violet flowers $(VV)$ in axial position $(AA)$ and white flowers $(vv)$ in terminal position $(aa)$. What phenotypic ratio of white flowers $(vv)$ did he receive in the $F_2$ generation (in $/16$)?

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$F_{1}$ progeny of a Mendelian dihybrid cross produces:

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