A grey-feathered chicken is crossed with anot | vedclass

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(A) This is a case of incomplete dominance where the grey phenotype is heterozygous $(Bb)$.Let $B$ represent black and $b$ represent white.The cross i

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All black

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(A) This is a case of incomplete dominance where the grey phenotype is heterozygous $(Bb)$.Let $B$ represent black and $b$ represent white.The cross is $Bb 	imes Bb$,resulting in $1$ $BB$ (black) : $2$ $Bb$ (grey) : $1$ $bb$ (white).Selfing the grey chickens $(Bb)$: The cross is $Bb 	imes Bb$,which results in $1$ $BB$ (black) : $2$ $Bb$ (grey) : $1$ $bb$ (white).Selfing the black chickens $(BB)$: The cross is $BB 	imes BB$,which results in all $BB$ (black) offspring.Since the question asks for the phenotype of the offspring produced by selfing the grey chickens and the black chickens separately,the grey selfing produces a ratio of $1:2:1$ (black:grey:white),while the black selfing produces all black offspring. Given the options,the question implies the result of selfing the grey chickens,which is $1$ $BB$ (black) : $2$ $Bb$ (grey) : $1$ $bb$ (white). However,if we look at the specific progeny mentioned,selfing grey $(Bb)$ results in $25\%$ black,$50\%$ grey,and $25\%$ white. If the question implies the result of selfing the black chickens $(BB)$,they are homozygous and will produce all black offspring.

$A$ grey-feathered chicken is crossed with another chicken of the same phenotype. The offspring are $15$ grey,$6$ black,and $8$ white. What will be the phenotype of the offspring produced by selfing the grey chickens and the black chickens from their progeny?

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