A polygenic trait is controlled by 3 genes A, | vedclass

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Question

(C) In a polygenic trait controlled by $n$ genes,the distribution of phenotypes in the $F_2$ generation follows the binomial expansion of $(a + b)^{2n

Vedclass · Accepted Answer

$15$

Vedclass · Answer

(C) In a polygenic trait controlled by $n$ genes,the distribution of phenotypes in the $F_2$ generation follows the binomial expansion of $(a + b)^{2n}$.Here,$n = 3$,so the expansion is $(a + b)^{2 	imes 3} = (a + b)^6$.The coefficients of the expansion $(a + b)^6$ are given by Pascal's triangle or the binomial theorem as $1, 6, 15, 20, 15, 6, 1$.Comparing this with the given ratio $1:6:x:20:x:6:1$,we find that $x = 15$.

$A$ polygenic trait is controlled by $3$ genes $A, B$,and $C$. In a cross $AaBbCc \times AaBbCc$,the phenotypic ratio of the offspring is observed as $1:6:x:20:x:6:1$. What is the possible value of $x$?

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