A man with blood group B marries a woman with | vedclass

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(C) The blood group $B$ can have two possible genotypes: $I^BI^B$ (homozygous) or $I^BI^O$ (heterozygous).Since the mother has blood group $A$,her gen

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$I^BI^O$

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(C) The blood group $B$ can have two possible genotypes: $I^BI^B$ (homozygous) or $I^BI^O$ (heterozygous).Since the mother has blood group $A$,her genotype is either $I^AI^A$ or $I^AI^O$.For the child to have blood group $B$,they must inherit the $I^B$ allele from the father.If the father is $I^BI^B$,the child would receive $I^B$ from him and either $I^A$ or $I^O$ from the mother,resulting in $I^AI^B$ ($AB$ group) or $I^BI^O$ ($B$ group).If the father is $I^BI^O$,the child could receive $I^B$ from the father and $I^O$ from the mother,resulting in $I^BI^O$ ($B$ group).Given the options provided,$I^BI^O$ is the most likely genotype for a child with blood group $B$ born to these parents,assuming the father is heterozygous $(I^BI^O)$ and the mother is heterozygous $(I^AI^O)$.

$A$ man with blood group $B$ marries a woman with blood group $A$. Their first child has blood group $B$. What is the genotype of their child?

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