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(B) During the resting state,the axonal membrane is more permeable to $K^+$ ions and nearly impermeable to $Na^+$ ions. When a stimulus is applied at

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$Na^+$ from extracellular fluid into intracellular fluid.

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(B) During the resting state,the axonal membrane is more permeable to $K^+$ ions and nearly impermeable to $Na^+$ ions. When a stimulus is applied at a site on the polarized membrane,the permeability to $Na^+$ ions increases rapidly. This leads to a rapid influx of $Na^+$ ions from the extracellular fluid into the intracellular fluid,causing a reversal of polarity at that site,which is known as depolarization or the action potential. Therefore,the action potential results from the movement of $Na^+$ from the extracellular fluid into the intracellular fluid.

During the propagation of a nerve impulse,the action potential results from the movement of which of the following?

Similar Questions

In which condition,the axonal membrane is comparatively more permeable to potassium ions and nearly impermeable to sodium ions?

During the nerve impulse (action potential),which ion has the highest permeability in the membrane?

When a neuron is in a resting state,i.e.,not conducting any impulse,the axonal membrane is:

When an impulse passes,the membrane is depolarized and the charge of the cells is

When a neuron is not conducting any impulse,$i.e$.,resting,the axonal membrane is comparatively more permeable to:

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