A, 5, ^oC rise in the temperature is observed | vedclass

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(C) Using the principle of conservation of energy,the electrical energy supplied to the conductor is converted into heat energy.$H = I^2Rt = mS\Delta

Vedclass · Accepted Answer

$20$

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(C) Using the principle of conservation of energy,the electrical energy supplied to the conductor is converted into heat energy.$H = I^2Rt = mS\Delta T$Here,$I$ is the current,$R$ is the resistance,$t$ is time,$m$ is mass,$S$ is specific heat,and $\Delta T$ is the rise in temperature.Since $R$,$t$,$m$,and $S$ are constant,we have $\Delta T \propto I^2$.Given that the initial rise in temperature $\Delta T_1 = 5\, ^oC$ for current $I_1 = I$.When the current is doubled,$I_2 = 2I$.Then,$\frac{\Delta T_2}{\Delta T_1} = \left(\frac{I_2}{I_1}ight)^2 = \left(\frac{2I}{I}ight)^2 = 4$.Therefore,$\Delta T_2 = 4 	imes \Delta T_1 = 4 	imes 5\, ^oC = 20\, ^oC$.

$A\, 5\, ^oC$ rise in the temperature is observed in a conductor by passing some current. When the current is doubled,then the rise in temperature will be equal to ............. $^oC$.

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