A mixture of 2 mol of carbon monoxide and 1 | vedclass

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Question

(B) The chemical reaction is: $2CO(g) + O_2(g) \rightarrow 2CO_2(g)$.The relationship between enthalpy change and internal energy change is given by:

Vedclass · Accepted Answer

$\Delta H < \Delta U$

Vedclass · Answer

(B) The chemical reaction is: $2CO(g) + O_2(g) \rightarrow 2CO_2(g)$.The relationship between enthalpy change and internal energy change is given by: $\Delta H = \Delta U + \Delta n_g RT$.Here,$\Delta n_g$ is the change in the number of moles of gaseous products and reactants: $\Delta n_g = n_p - n_r = 2 - (2 + 1) = 2 - 3 = -1$.Since $\Delta n_g = -1$,the equation becomes: $\Delta H = \Delta U - RT$.Therefore,$\Delta H < \Delta U$.

$A$ mixture of $2 \ mol$ of carbon monoxide and $1 \ mol$ of oxygen is ignited in a closed vessel to form carbon dioxide. If $\Delta H$ is the enthalpy change and $\Delta U$ is the change in internal energy,then:

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