One mole of a gas expands from 1 , L to 5 , L | vedclass

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Question

(A) The work done during expansion against a constant external pressure is given by the formula: $W = -P_{ext} \Delta V$. Given: $P_{ext} = 1 \, atm$

Vedclass · Accepted Answer

$405.2$

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(A) The work done during expansion against a constant external pressure is given by the formula: $W = -P_{ext} \Delta V$. Given: $P_{ext} = 1 \, atm$ $V_1 = 1 \, L$ $V_2 = 5 \, L$ $\Delta V = V_2 - V_1 = 5 \, L - 1 \, L = 4 \, L$. Substituting the values: $W = -(1 \, atm) 	imes (4 \, L) = -4 \, L \cdot atm$. Converting to Joules: $W = -4 	imes 101.3 \, J = -405.2 \, J$. The negative sign indicates that work is done by the system on the surroundings.

One mole of a gas expands from $1 \, L$ to $5 \, L$ against a constant external pressure of $1 \, atm$. How much work is done in Joules (in $, J$)? $(1 \, L \cdot atm = 101.3 \, J)$

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