The equivalent mass of a divalent metal is 32 | vedclass

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Question

(C) The relationship between equivalent mass,atomic mass,and valency is given by: $	ext{Equivalent mass} = \frac{	ext{Atomic mass}}{	ext{Valency}}$

Vedclass · Accepted Answer

$188$

Vedclass · Answer

(C) The relationship between equivalent mass,atomic mass,and valency is given by: $	ext{Equivalent mass} = \frac{	ext{Atomic mass}}{	ext{Valency}}$.Given that the metal is divalent,its valency is $2$. Therefore,the atomic mass of the metal is $	ext{Atomic mass} = 32 	imes 2 = 64 \ g/mol$.The formula for the nitrate salt of a divalent metal $M$ is $M(NO_3)_2$.The molar mass of $M(NO_3)_2$ is calculated as: $	ext{Molar mass} = 	ext{Atomic mass of } M + 2 	imes (	ext{Atomic mass of } N + 3 	imes 	ext{Atomic mass of } O)$.Substituting the values: $	ext{Molar mass} = 64 + 2 	imes (14 + 3 	imes 16) = 64 + 2 	imes (14 + 48) = 64 + 2 	imes (62) = 64 + 124 = 188 \ g/mol$.

Isotope	Natural abundance (%)	Molar mass $(u)$
$^{35}Cl$	$75.77$	$34.9689$
$^{37}Cl$	$24.23$	$36.9659$

The equivalent mass of a divalent metal is $32$. What is the molar mass of its nitrate salt?

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