How many moles of $NaOH$ are present in $27 \, mL$ of $0.15 \, M \, NaOH$?

  • A
    $2.27 \times 10^4$
  • B
    $2.67 \times 10^{-4}$
  • C
    $4.05 \times 10^{-3}$
  • D
    $3.34 \times 10^2$

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