Calculate the number of molecules in a gas sa | vedclass

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Question

(A) At $NTP$,$22400 \, cc$ of a gas contains $6.022 	imes 10^{23}$ molecules.Therefore,$1 \, cc$ of gas contains $\frac{6.022 	imes 10^{23}}{22400}$

Vedclass · Accepted Answer

$3.01 	imes 10^{12}$

Vedclass · Answer

(A) At $NTP$,$22400 \, cc$ of a gas contains $6.022 	imes 10^{23}$ molecules.Therefore,$1 \, cc$ of gas contains $\frac{6.022 	imes 10^{23}}{22400}$ molecules.For $1.12 	imes 10^{-7} \, cc$ of gas,the number of molecules is $\frac{6.022 	imes 10^{23}}{22400} 	imes 1.12 	imes 10^{-7}$.$= \frac{6.022 	imes 10^{23} 	imes 1.12 	imes 10^{-7}}{2.24 	imes 10^4} = 3.011 	imes 10^{12}$ molecules.

Calculate the number of molecules in a gas sample having a volume of $1.12 \times 10^{-7} \, cc$ at $NTP$.

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