For the reaction SO_2 + 2H_2S to 3S + 2H_2O,w | vedclass

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(B) In the reaction $SO_2 + 2H_2S 	o 3S + 2H_2O$,the oxidation state of $S$ in $SO_2$ changes from $+4$ to $0$ (reduction).Thus,$SO_2$ acts as the ox

Vedclass · Accepted Answer

$32$

Vedclass · Answer

(B) In the reaction $SO_2 + 2H_2S 	o 3S + 2H_2O$,the oxidation state of $S$ in $SO_2$ changes from $+4$ to $0$ (reduction).Thus,$SO_2$ acts as the oxidizing agent.The change in oxidation state per molecule of $SO_2$ is $|4 - 0| = 4$.The equivalent weight of $SO_2$ is $\frac{	ext{Molar Mass}}{n	ext{-factor}} = \frac{64}{4} = 16$.Twice the equivalent weight is $16 	imes 2 = 32$.

For the reaction $SO_2 + 2H_2S \to 3S + 2H_2O$,which option represents twice the equivalent weight of the oxidizing agent?

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