(C) Molarity $(M)$ is given by the formula: $M = \frac{\text{mass percentage} \times \text{density} \times 10}{\text{Molar mass}}$.Given: $M = 3.6 \,

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(C) Molarity $(M)$ is given by the formula: $M = \frac{\text{mass percentage} \times \text{density} \times 10}{\text{Molar mass}}$.Given: $M = 3.6 \, mol \, L^{-1}$,$\text{mass percentage} = 29 \%$,$\text{Molar mass} = 98 \, g \, mol^{-1}$.Substituting the values: $3.6 = \frac{29 \times d \times 10}{98}$.$d = \frac{3.6 \times 98}{290} = \frac{352.8}{290} \approx 1.216 \, g \, mL^{-1}$.Rounding to two decimal places,the density is $1.22 \, g \, mL^{-1}$.

Class 12 Chemistry Solutions Method of expressing concentration of solution

Medium

If a $3.6 \, M$ solution of $H_2SO_4$ contains $29 \% \, H_2SO_4$ by mass,find the density of the $H_2SO_4$ solution. (Molar mass of $H_2SO_4 = 98 \, g \, mol^{-1}$)

A
$1.64 \, g \, mL^{-1}$
B
$1.88 \, g \, mL^{-1}$
C
$1.22 \, g \, mL^{-1}$
D
$1.45 \, g \, mL^{-1}$

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Method of expressing concentration of solution

$10.6 \, g$ of a substance of molecular weight $106$ was dissolved in $100 \, mL$. $10 \, mL$ of this solution was pipetted out into a $1000 \, mL$ flask and made up to the mark with distilled water. The molarity of the resulting solution is

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An aqueous solution contains $28\%$ by weight of a liquid $A$ $(m_w = 140)$. The mole fraction of liquid $A$ is:

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When $120 \ g$ of urea (molar mass $= 60 \ g/mol$) is dissolved in $1000 \ g$ of water,the density of the resulting solution is $1.15 \ g/mL$. The molarity of this solution is ........ $M$.

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What volume of water in $mL$ is required to prepare a $0.20\,N$ solution from $1600\,mL$ of a $0.2050\,N$ solution?

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The sum of the mole fraction of the components of a solution is

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If a $3.6 \, M$ solution of $H_2SO_4$ contains $29 \% \, H_2SO_4$ by mass,find the density of the $H_2SO_4$ solution. (Molar mass of $H_2SO_4 = 98 \, g \, mol^{-1}$)

Similar Questions

$10.6 \, g$ of a substance of molecular weight $106$ was dissolved in $100 \, mL$. $10 \, mL$ of this solution was pipetted out into a $1000 \, mL$ flask and made up to the mark with distilled water. The molarity of the resulting solution is

An aqueous solution contains $28\%$ by weight of a liquid $A$ $(m_w = 140)$. The mole fraction of liquid $A$ is:

When $120 \ g$ of urea (molar mass $= 60 \ g/mol$) is dissolved in $1000 \ g$ of water,the density of the resulting solution is $1.15 \ g/mL$. The molarity of this solution is ........ $M$.

What volume of water in $mL$ is required to prepare a $0.20\,N$ solution from $1600\,mL$ of a $0.2050\,N$ solution?

The sum of the mole fraction of the components of a solution is

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