What is the total number of electrons present | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Density = Mass / Volume. Mass of water = $1 \ g/mL 	imes 18 \ mL = 18 \ g$. Moles of water = $18 \ g / 18 \ g/mol = 1 \ mol$. $1 \ mol$ of $H_2O$

Vedclass · Accepted Answer

$6.022 	imes 10^{24}$

Vedclass · Answer

(B) Density = Mass / Volume. Mass of water = $1 \ g/mL 	imes 18 \ mL = 18 \ g$. Moles of water = $18 \ g / 18 \ g/mol = 1 \ mol$. $1 \ mol$ of $H_2O$ contains $6.022 	imes 10^{23}$ molecules of $H_2O$. Each $H_2O$ molecule contains $2$ electrons from $2H$ atoms and $8$ electrons from $1O$ atom,so total electrons per molecule = $2 + 8 = 10 \ e^-$. Total electrons = $1 \ mol 	imes 6.022 	imes 10^{23} 	ext{ molecules/mol} 	imes 10 	ext{ electrons/molecule} = 6.022 	imes 10^{24} \ e^-$.

What is the total number of electrons present in $18 \ mL$ of water? (Density of water = $1 \ g/mL$)

Similar Questions

What is the number of molecules of $SO_2$ present in $64 \ g$ of $SO_2$?

Which of the following substances consists of a total of $1 \ mol$ of atoms? (Molar mass of $NH_3 = 17 \ g/mol, H_2O = 18 \ g/mol, N_2 = 28 \ g/mol, CO_2 = 44 \ g/mol$)

How many moles of magnesium phosphate,$Mg_{3}(PO_{4})_{2}$ will contain $0.25 \ mol$ of oxygen atoms?

Number of atoms in $11.2 \, L$ of $CO_2$ at $NTP$ is .............. $N_A$

Which of the following contains the maximum number of atoms?

Vedclass Test Series

Exam Paper Generator

Online Exam Module