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Question

(A) The balanced chemical equation for the combustion of propane is: $C_3H_{8(g)} + 5O_{2(g)} \rightarrow 3CO_{2(g)} + 4H_2O_{(l)}$.According to the s

Vedclass · Accepted Answer

$560$

Vedclass · Answer

(A) The balanced chemical equation for the combustion of propane is: $C_3H_{8(g)} + 5O_{2(g)} ightarrow 3CO_{2(g)} + 4H_2O_{(l)}$.According to the stoichiometry,$1$ mole of $C_3H_8$ requires $5$ moles of $O_2$.For $5$ moles of $C_3H_8$,the moles of $O_2$ required are $5 	imes 5 = 25$ moles.Assuming the question asks for the volume of $O_2$ at $STP$ (Standard Temperature and Pressure),the volume is calculated as: $	ext{Volume} = 	ext{moles} 	imes 22.4 	ext{ L/mol}$.$	ext{Volume} = 25 	ext{ mol} 	imes 22.4 	ext{ L/mol} = 560 	ext{ L}$.Thus,the correct option is $A$.

The volume of $O_2$ required for the complete combustion of $5$ moles of propane $(C_3H_8)$ at $25$ $^\circ C$ is ............... liters.

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