Ammonia contains 82.35% nitrogen and 17.65% h | vedclass

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(D) In $NH_3$,$17.65 \ g$ of hydrogen combines with $82.35 \ g$ of nitrogen. $1 \ g$ of hydrogen combines with $\frac{82.35}{17.65} = 4.67 \ g$ of nit

Vedclass · Accepted Answer

Law of Reciprocal Proportions

Vedclass · Answer

(D) In $NH_3$,$17.65 \ g$ of hydrogen combines with $82.35 \ g$ of nitrogen. $1 \ g$ of hydrogen combines with $\frac{82.35}{17.65} = 4.67 \ g$ of nitrogen. In $H_2O$,$11.10 \ g$ of hydrogen combines with $88.90 \ g$ of oxygen. $1 \ g$ of hydrogen combines with $\frac{88.90}{11.10} = 8.01 \ g$ of oxygen. The ratio of the masses of $N$ and $O$ that combine with a fixed mass $(1.0 \ g)$ of hydrogen is $4.67 : 8.01 = 1 : 1.72$. In $NO_2$,the ratio of $N$ and $O$ that combine with each other is $36.85 : 63.15 = 1 : 1.71$. Since both ratios are the same,the Law of Reciprocal Proportions is illustrated.

Ammonia contains $82.35\%$ nitrogen and $17.65\%$ hydrogen. Water contains $88.90\%$ oxygen and $11.10\%$ hydrogen. Nitrogen dioxide contains $63.15\%$ oxygen and $36.85\%$ nitrogen. Which law can be illustrated by the given data?

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