What is the total number of electrons present | vedclass

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(B) Density of water is $1 \ g/mL$,so $18 \ mL$ of water is equal to $18 \ g$ of water.Molar mass of $H_2O = (2 	imes 1) + 16 = 18 \ g/mol$.Number of

Vedclass · Accepted Answer

$6.023 	imes 10^{24}$

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(B) Density of water is $1 \ g/mL$,so $18 \ mL$ of water is equal to $18 \ g$ of water.Molar mass of $H_2O = (2 	imes 1) + 16 = 18 \ g/mol$.Number of moles of $H_2O = \frac{18 \ g}{18 \ g/mol} = 1 \ mol$.One molecule of $H_2O$ contains $10$ electrons ($2$ from $H$ and $8$ from $O$).Total number of electrons = $1 \ mol 	imes 10 	imes 6.023 	imes 10^{23} \ mol^{-1} = 6.023 	imes 10^{24}$ electrons.

What is the total number of electrons present in $18 \ mL$ of water?

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