If 74.5 g of a metallic chloride contains 35 | vedclass

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(C) Mass of metallic chloride $= 74.5 \ g$. Mass of chlorine $= 35.5 \ g$. Mass of metal $= 74.5 \ g - 35.5 \ g = 39 \ g$. The equivalent mass of a me

Vedclass · Accepted Answer

$39$

Vedclass · Answer

(C) Mass of metallic chloride $= 74.5 \ g$. Mass of chlorine $= 35.5 \ g$. Mass of metal $= 74.5 \ g - 35.5 \ g = 39 \ g$. The equivalent mass of a metal is given by the formula: $	ext{Equivalent mass of metal} = \frac{	ext{Mass of metal}}{	ext{Mass of chlorine}} 	imes 	ext{Equivalent mass of chlorine}$. Since the equivalent mass of chlorine is $35.5$,we have: $	ext{Equivalent mass of metal} = \frac{39}{35.5} 	imes 35.5 = 39$.

Isotope	$\%$ Natural Abundance	Molar Mass $(g/mol)$
$^{35}Cl$	$75.77$	$34.9689$
$^{37}Cl$	$24.23$	$36.9659$

If $74.5 \ g$ of a metallic chloride contains $35.5 \ g$ of chlorine,then the equivalent mass of the metal will be ...... .

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