(B) The molar mass of methane $(CH_4)$ is $12 + 4 \times 1 = 16 \ g/mol$. Number of moles = $\frac{\text{Given mass}}{\text{Molar mass}} = \frac{16 \

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(B) The molar mass of methane $(CH_4)$ is $12 + 4 \times 1 = 16 \ g/mol$. Number of moles = $\frac{\text{Given mass}}{\text{Molar mass}} = \frac{16 \ g}{16 \ g/mol} = 1 \ mol$. Number of molecules = $\text{Number of moles} \times N_A = 1 \times 6.022 \times 10^{23} = 6.022 \times 10^{23}$. Thus,the value is $6.02 \times 10^{23}$.