In the test for SO_4^{2-},the white precipita | vedclass

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(D) The test for sulfate ions $(SO_4^{2-})$ involves adding barium chloride $(BaCl_2)$ solution to the test solution,which results in the formation of

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None of the above

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(D) The test for sulfate ions $(SO_4^{2-})$ involves adding barium chloride $(BaCl_2)$ solution to the test solution,which results in the formation of a white precipitate of barium sulfate $(BaSO_4)$.$Ba^{2+} + SO_4^{2-} ightarrow BaSO_4 (s) 	ext{ (white precipitate)}$Barium sulfate $(BaSO_4)$ is highly insoluble in water and common mineral acids like $HCl$,$H_2SO_4$,and $HNO_3$ at room temperature.Therefore,it does not dissolve in any of the given solutions.

In the test for $SO_4^{2-}$,the white precipitate of sulfate is soluble in which of the following solutions?

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