Phosphoric acid (H_3PO_4) is a tribasic acid, | vedclass

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(C) The chemical reaction for the conversion of $NaH_2PO_4$ to $Na_3PO_4$ is: $NaH_2PO_4 + 2NaOH \rightarrow Na_3PO_4 + 2H_2O$ From the stoichiometry,

Vedclass · Accepted Answer

$200$

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(C) The chemical reaction for the conversion of $NaH_2PO_4$ to $Na_3PO_4$ is: $NaH_2PO_4 + 2NaOH ightarrow Na_3PO_4 + 2H_2O$ From the stoichiometry,$1 \, mole$ of $NaH_2PO_4$ reacts with $2 \, moles$ of $NaOH$. Number of moles of $NaH_2PO_4 = \frac{	ext{mass}}{	ext{molar mass}} = \frac{12 \, g}{120 \, g/mol} = 0.1 \, mol$. Therefore,moles of $NaOH$ required $= 2 	imes 0.1 = 0.2 \, mol$. Using the molarity formula $M = \frac{n}{V(L)}$,we have $V(L) = \frac{n}{M} = \frac{0.2 \, mol}{1 \, M} = 0.2 \, L$. Converting to $mL$,$V = 0.2 	imes 1000 = 200 \, mL$.

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