In a solution containing Hg^{2+}, Cd^{2+}, Sr | vedclass

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(A) In qualitative analysis,$H_2S$ in the presence of $0.3 \, M \, HCl$ is used to precipitate Group-$II$ cations.Group-$II$ cations include $Hg^{2+},

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$Cd^{2+}, Cu^{2+},$ and $Hg^{2+}$

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(A) In qualitative analysis,$H_2S$ in the presence of $0.3 \, M \, HCl$ is used to precipitate Group-$II$ cations.Group-$II$ cations include $Hg^{2+}, Pb^{2+}, Bi^{3+}, Cu^{2+}, Cd^{2+}, As^{3+}, Sb^{3+},$ and $Sn^{4+}$.Among the given ions $(Hg^{2+}, Cd^{2+}, Sr^{2+}, Fe^{2+}, Cu^{2+})$,the ions $Hg^{2+}, Cd^{2+},$ and $Cu^{2+}$ belong to Group-$II$.$Sr^{2+}$ belongs to Group-$V$ and $Fe^{2+}$ belongs to Group-$III$,which do not precipitate under these acidic conditions.Therefore,$Hg^{2+}, Cd^{2+},$ and $Cu^{2+}$ will precipitate as their respective sulfides.

In a solution containing $Hg^{2+}, Cd^{2+}, Sr^{2+}, Fe^{2+},$ and $Cu^{2+}$ ions in $0.3 \, M \, HCl$,which ions will precipitate upon the addition of $H_2S$?

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