Which substance precipitates when HCl is adde | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) When $SnS$ is dissolved in yellow ammonium sulfide $(NH_4)_2S_x$,it forms a soluble complex,ammonium thiostannate,$(NH_4)_2SnS_3$. The reaction is

Vedclass · Accepted Answer

$SnS_2$

Vedclass · Answer

(B) When $SnS$ is dissolved in yellow ammonium sulfide $(NH_4)_2S_x$,it forms a soluble complex,ammonium thiostannate,$(NH_4)_2SnS_3$. The reaction is: $SnS + (NH_4)_2S_2 \rightarrow (NH_4)_2SnS_3$. When $HCl$ is added to this solution,the complex decomposes to precipitate $SnS_2$ (tin$(IV)$ sulfide) as a yellow precipitate. The reaction is: $(NH_4)_2SnS_3 + 2HCl \rightarrow SnS_2 + 2NH_4Cl + H_2S$.

Which substance precipitates when $HCl$ is added to a solution of $SnS$ in yellow ammonium sulfide?

Similar Questions

If the solubility product of $CaSO_4$ is $2.5 \times 10^{-5}$,then its solubility will be .......

The solubility of $AgCl$ in $0.2 \ M \ NaCl$ solution ($K_{sp}$ for $AgCl = 1.20 \times 10^{-10}$) is:

The solubility product of $NiS$ is $4.9 \times 10^{-5}$ at $298 \ K$. Calculate its solubility in $mol \ dm^{-3}$ at the same temperature?

At $25^{\circ} C$,the solubility product of $MCl$ is $1 \times 10^{-10}$. What is its molar solubility in $0.1 \ M \ NaCl$ solution at the same temperature?

If the solubility of calcium hydroxide is $\sqrt{3}$,then its solubility product will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module