When calomel reacts with a solution of $NH_4OH$,which compound is formed?

Upon treatment with ammoniacal $H_2S$,the metal ion that precipitates as a sulfide is

Sodium nitroprusside when reacts with a solution of $Na_2S$,produces:

The distinguishing reagent between silver and lead salts is:

When $H_2S$ gas is passed through the $HCl$ containing aqueous solutions of $CuCl_2$,$HgCl_2$,$BiCl_3$ and $CoCl_2$,which does not precipitate out?

$Pb^{2+}$,$Cu^{2+}$,$Zn^{2+}$,and $Ni^{2+}$ ions are present in a given acidic solution. On passing hydrogen sulphide gas through this solution,the precipitate formed will contain: