(C) When $Na_2O_2$ is added to the mixture,$Fe^{2+}$ is oxidized to $Fe^{3+}$,which precipitates as $Fe(OH)_3$ (brown residue).$Al^{3+}$ forms soluble

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Yellow filtrate and brown residue

(C) When $Na_2O_2$ is added to the mixture,$Fe^{2+}$ is oxidized to $Fe^{3+}$,which precipitates as $Fe(OH)_3$ (brown residue).$Al^{3+}$ forms soluble $[Al(OH)_4]^-$ and $Cr^{3+}$ is oxidized to $CrO_4^{2-}$ (yellow filtrate).Thus,the filtrate is yellow due to the presence of chromate ions,and the residue is brown due to the presence of ferric hydroxide.

Class 12 Chemistry Principles Related to Practical Chemistry Wet Test for Basic Radical

Medium

An aqueous solution containing $FeSO_4$,$Al_2(SO_4)_3$,and chrome alum is treated with $Na_2O_2$ and heated,followed by filtration. The resulting products are:

A
Colorless filtrate and green residue
B
Yellow filtrate and green residue
C
Yellow filtrate and brown residue
D
Green filtrate and brown residue

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Wet Test for Basic Radical

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An aqueous solution containing $FeSO_4$,$Al_2(SO_4)_3$,and chrome alum is treated with $Na_2O_2$ and heated,followed by filtration. The resulting products are:

Similar Questions

What precipitate is formed when $SnCl_2$ is added to $HgCl_2$?

On saturating an aqueous solution of $Cu(II)$,$Pb(II)$,and $Zn(II)$ ions with $H_2S$,which of the following will precipitate?

Three separate samples of a solution of a single salt gave these test results: one formed a white precipitate with excess ammonia solution,one formed a white precipitate with dilute $NaCl$ solution,and one formed a black precipitate with $H_2S$. The salt could be:

Upon treatment with ammoniacal $H_2S$,the metal ion that precipitates as a sulfide is

Which of the following compounds changes the color of an aqueous $FeCl_3$ solution?

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